MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Vector Addition

Let the base ...

Question

Let the base of a triangle lie along the line x=a and be of length 2a. The area of triangle is $a^{2}$ , if the vertex lies on the line.

Open in App

Solution

$\begin{matrix} A r e a o f t r i a n g l e = \frac{1}{2} \times 2 a \times h = a^{2} \Rightarrow h = a \Rightarrow V e r t e x l i e s o n e i t h e r l i n e . x = 2 a o r x = 0. \end{matrix}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Let the base of a triangle lie along the line

x = a

and be of length

a

. The area of this triangle is

a^{2}

, if the vertex lies on the line

Q. The base of a triangle lies along the line

x = a

and is of length a. The area of the triangle is

a^{2} .

The locus of the third vertex is

Q. The base of a triangle lies along

x = a

and is of length

a

. If the area of the triangle is

a^{2}

, then the locus of its vertex is

Q. I: A straight line is such that the algebraic sum of the distance from any no. of fixed points is zero. Then that line always passes through a fixed point
II: The base of the triangle lie along the line

x = a

and is of length

a .

If the area of the triangle is

a^{2}

then the third vertex lies on

x = - a

x = 3 a

Then which of the following is true.

Q. The vertices of the base of an isosceles triangle lie on a parabola

y^{2} = 4 x

and the base is a part of the line

y = 2 x - 4

. If the third vertex of the triangle lies on the

x

-axis, its coordinates are

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Basic Operations

PHYSICS

Watch in App

explore_more_icon

Explore more

Vector Addition

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon