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Question

Let the degree of polynomial (x51+x)9(x51x)9 be α then α192 is___.

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Solution

The expression (x51+x)9((x51)x)9 is a polynomial of degree 21
So 21192=1
Let x51=λ
(λ+x)9(λx)9=(9C0λ9+9C1λ8x+9C2λ7x2+....)(9C0λ99C1λ8x+.....)(9C0λ99C1λ8x+...)=2(9C1λ8x+9C3λ6x3+....)2(9(x51)4x)+9C3(x51)3x3....
degree of polynomial = 21.


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