Let the eccentricity of the hyperbola x2a2−y2b2=1 be reciprocal to that of the ellipse x2+4y2=4. If the hyperbola passes through a focus of the ellipse, then:
A
Equation of hyperbola is x23−y22=1
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B
a focus of hyperbola is (2,0)
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C
eccentricity of the hyperbola is 2√3
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D
Equation of hyperbola is x2−3y2=3
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Solution
The correct options are B a focus of hyperbola is (2,0) DEquation of hyperbola is x2−3y2=3