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Question

Let the function f:[0,)R be defined by f(x)=2x+sinx. Then f is

A
bijective function
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B
injective but not surjective
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C
surjective but not injective
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D
neither injective nor surjective
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Solution

The correct option is A bijective function
f(x)=2x+sinx
f(x)=2+cosx>0 for all x[0,)
f is strictly increasing on [0,)
f is injective function.

For y=10,
2x+sinx=10
2x+10=sinx which has no solution in [0,) as 2x+1010
f is not surjective.

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