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Question

Let the function f(x)=sinx+cosx, be defined in [0,2π], then f(x)

A
increases in (π4,π2)
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B
decreases in [π4,5π4]
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C
increases in [0,π4][π,2π]
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D
decreases in [0,π4)(π2,2π]
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Solution

The correct option is B decreases in [π4,5π4]
For increasing /decreasing we need f'(x)
f(x)=cosxsinx=2(sin(π4x))
it is negative in :[π4,5π4]: f(x) decreases
it is positive in :[0,π4][5π4,2π] :f(x) increases

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