Let the least number of six digits which when divided by 4, 6, 10 and 15 leaves in each case the same remainder of 2 be N What is the sum of the digits of N?

Open in App

Solution

L.C.M. of 4, 6, 10 and 15 = 60 Least number of six digits = 100000
Dividing 100000 by 60 we get remainder = 40
$∴$ Least number of six digits divisible by 4, 6, 10 and 15
= 100000 + (60 - 40) = 100020
$∴$ N = 100020 + 2 = 100022
$∴$ Sum of digits in N = 1 + 0 + 0 + 0 + 2 + 2 = 5

Suggest Corrections

Similar questions

Q. Let the least number of six digits which when divided by

4, 6, 10

and

15

leaves in each case same remainder

2

N .

The sum of digits of

N

Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is :

Q. Find the sum of a least six digits number, which when divided by 4, 6, 10 and 15 leaves the remainder of 2 in each case.

Q. The largest number of five digits which when divided by

16, 24, 30 o r 36

leaves the same remainder

10

in each case is

Q. Find the least three digit number which when divided by 20, 30, 40 and 50 leaves remainder 10 in each case.

Join BYJU'S Learning Program

Let the least number of six digits which when divided by 4, 6, 10 and 15 leaves in each case the same remainder of 2 be N What is the sum of the digits of N?

L.C.M. of 4, 6, 10 and 15 = 60 Least number of six digits = 100000Dividing 100000 by 60 we get remainder = 40∴ Least number of six digits divisible by 4, 6, 10 and 15= 100000 + (60 - 40) = 100020∴ N = 100020 + 2 = 100022∴ Sum of digits in N = 1 + 0 + 0 + 0 + 2 + 2 = 5

L.C.M. of 4, 6, 10 and 15 = 60 Least number of six digits = 100000
Dividing 100000 by 60 we get remainder = 40
$∴$ Least number of six digits divisible by 4, 6, 10 and 15
= 100000 + (60 - 40) = 100020
$∴$ N = 100020 + 2 = 100022
$∴$ Sum of digits in N = 1 + 0 + 0 + 0 + 2 + 2 = 5