Let the line 4x+3y+1=0 meets the parabola 8y2=ax at P,Q. If the angle made by chord PQ at the vertex of the parabola in 90°, then |a|=
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Solution
Given line 4x+3y+1=0⇒1=−(4x+3y) For the given parabola the vertex will be origin Hence the pair of lines joinig the vertex to the intersection point of line and parabola will be 8y2=a(−4x−3y)x⇒8y2+4ax2+3axy=0 For the pair of line to make right angle at origin coefficient of x2+coefficient of y2=0⇒a=−2