The correct option is C 24 gm
Taking the basis as 100 g of the compound, it has 75 g metal and 25 g oxygen in it.
mM=75 g, mO=25 g
The number of equivalents of both the metal and oxygen must be the same in the compound.
(nE)metal = (nE)oxide
nE=Given massEquivalent mass=mMEM
EM=mM(nE)oxide
The oxide ion which has a molar mass of 16 g/mol has a negative two charge, so its equivalent mass:
EO=162=8 g
EM=75×825=24 g