Let the maximum and minimum distance from origin to the curve (z¯z−32√2[(z+¯z)−i(z−¯z)−√2=0 are r1 and r2 respectively then r1+r2=
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is C 3 Let z = x + iy Given curve is x2+y2−3√2+3√2y−√2=0 Let distance from centre (32√2,32√2) to origin is d=32 Then maximum distance from origin = d + r Minimum distance from origin = d - r ∴r1+r2=2d=3