Case (i): Total letters = 26 and Total digits = 10
If three letters on plate be represented by alphabets then first place can be filled in 26 ways,
Second place can again be filled in 26 ways (∵ repetition is allowed)
And third place can also be filled in 26 ways.
Hence, three letters can be filled by 26×26×26=(26)3 ways
And three digit numbers on the plate in 999 ways (i.e.001, 002,..., 999)
Hence, by principle of multiplication, the required number of ways =(26)3(999)
Case (ii): Here the three letters out of 26 can be filled in 26P3(∵ repetition is not allowed)
And three digit can be filled out of 10 in 10P3(∵ repetition is not allowed)
Hence, the required number of ways =( 26P3)( 10P3)