Let the pairs of vectors →a,→b and →c,→d each determines a plane, then the planes are parallel if
A
(→a×→c)×(→b×→d)=→0
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B
(→a×→c).(→b×→d)=→0
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C
(→a×→b)×(→c×→d)=→0
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D
(→a×→b)⋅(→c×→d)=→0
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Solution
The correct option is C(→a×→b)×(→c×→d)=→0 Normal vector to plane ¯a,¯b is given by, ¯aׯb And normal vector to plane ¯c,¯d is given by, ¯cׯd Now for planes to be parallel, the angle between their normal should be 0∘ or 180∘