Let the point P represent the complex number z. If OP is turned round O by an angle π2 in the clockwise sense where O is the origin then in the new position of P represents the complex number .................
A
- z
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B
- iz
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C
z
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D
iz
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Solution
The correct option is B - iz Rotation due to anticlockwise is positive and in clockwise sense is negative. Hence Let z=eiθ =cosθ+isinθ Now if we rotate it by π2 in clockwise sense , we get cos(θ−π2)+isin(θ−π2) =sinθ−icosθ =−i(isinθ+cosθ) =−i(cosθ+isinθ) =−iz