Let the probability that a batter gets a hit is $1 / 4$ . If he plays $4$ bats the probability that he gets at least one hit is

175 / 256

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Solution

The correct option is A $175 / 256$
Prob. that Batter gets hit = 1/4
Prob. that he gets at least are hit, it
he blogs y bats is :-
$= (1 - 0.25) (1 - 0.25) (1 - 0.25) (1 - 0.25)$
$= (1 - \frac{1}{4})^{4}$
$P = (\frac{3}{4})^{4} \Rightarrow (\frac{81}{256})$

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Let the probability that a batter gets a hit is 1/4. If he plays 4 bats the probability that he gets at least one hit is

The correct option is A 175/256Prob. that Batter gets hit = 1/4 Prob. that he gets at least are hit, it he blogs y bats is :-=(1−0.25)(1−0.25)(1−0.25)(1−0.25)=(1−14)4P=(34)4⇒(81256)

Let the probability that a batter gets a hit is $1 / 4$ . If he plays $4$ bats the probability that he gets at least one hit is

The correct option is A $175 / 256$
Prob. that Batter gets hit = 1/4
Prob. that he gets at least are hit, it
he blogs y bats is :-
$= (1 - 0.25) (1 - 0.25) (1 - 0.25) (1 - 0.25)$
$= (1 - \frac{1}{4})^{4}$
$P = (\frac{3}{4})^{4} \Rightarrow (\frac{81}{256})$