Let the relation R be defined on N by aRb iff 2a + 3b = 30. Then write R as a set of ordered pairs.

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Solution

As, R = {(a, b) : 2a + 3b = 30; a, b $\in$ N}

So, R = {(3, 8), (6, 6), (9, 4), (12, 2)}

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Let the relation R be defined on N by aRb iff 2a + 3b = 30. Then write R as a set of ordered pairs.

As, R = {(a, b) : 2a + 3b = 30; a, b ∈ N}So, R = {(3, 8), (6, 6), (9, 4), (12, 2)}

As, R = {(a, b) : 2a + 3b = 30; a, b $\in$ N}

So, R = {(3, 8), (6, 6), (9, 4), (12, 2)}