According to Ohm’s law
V = IR
⇒I=VR...(1)
Now, potential difference is decreased to half.
∴ New potential difference V′=V2
Resistance remains constant.
So the new current, I′=V′R
=(V2)R
=(12)(VR)
=(12)I=I2
Therefore, the amount of current flowing through the electrical component is reduced by half.