wiz-icon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

Let the solubilities of AgCl in pure water, 0.01 M CaCl2, 0.01 M NaCl % 0.05 M AgNO3 be s1,s2,s3 & s4 respectively. What is the correct order of these quantities ? Neglect any complexation.

A
s1>s4>s3>s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
s1>s2=s3>s4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
s1>s3>s2>s4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
s4>s2>s3>s1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C s1>s3>s2>s4
Given
Conc. of CaCl2 is 0.01
Conc. of NaCl is 0.01
Conc. of Ag2NO3 is 0.05
Solution
Solubility is inversely proportion to conc. of common ion.
Therefore Water Have most solubility because there is no common ion
AgNO3 have least solubility because highest conc. of Ag ion (0.05)
CaCl2 is less soluble than NaCl because it produces moreClion.
The correct answer is C

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon