Let the vectors a and b be such that |a|=3 and |b|=√23, then a×b is a unit vector, if the angle between a and b is
a) π6
b) π4
c) π3
d) π2
It is given that |a|=3 and |b|=√23
Let θ be the angle between a and b, then |a×b|=1
⇒|a||b| sin θ=1⇒3×√23×sin θ=1⇒sin θ=1√2⇒θ=π4
Hence, a×b is a unit vector, if the angle between a and b is π4.