Let the vectors a, b, c and d be such that (a×b)×(c×d)=0. Let P1and P2be planes determined by pair of vectors a, b and c, d respectively. Then the angle between P1and P2is
A
0∘
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B
π4
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C
π3
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D
π2
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Solution
The correct option is A0∘ A vector perpendicular to the planeP1 of a,b is a×b A vector perpendicular to the planeP2 of c,d is c×d. ⇒(a×b)×(c×d)=0⇒(a×b)∥(c×d) ∴The angle between the planes is 0∘.