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Permutation under Restriction

Let there are...

Question

Let there are $4$ red, $3$ yellow and $2$ green balls, then the total number of arrangements in a row .

A

5!

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B

4!

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C

9!

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D

none of these

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Solution

The correct option is C 9!
Given

There are $4$ red, $3$ yellow and $2$ green balls

Total numbe of Bals is $4 + 3 + 2 = 9$

NO .of arrangements is given as $9!$

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