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Question

Let there be an A.P with first term a, common difference d. If an denotes its nth term and Sn the sum of first n terms, , if an=4,d=2 and Sn=14 then|n+a| is

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Solution

Given,

d=2

an=a+(n1)d

4=a+(n1)2

4=a+2n2

a+2n=6

Sn=n2[2a+(n1)d]

14=n[a+n1]

14=n[62n+n1]
14=n[5n]
14=n[n5]
7[75]=n[n5]
n=7

And,a+2(7)=6a=8

|a+n|=|8+7|=|1|=1




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