Question

Let there be two integers such that one integer is $3$ more than the other and their product is $70$. Find the two integers.

• A. $7$ and $10$
• B. $6$ and $9$
• C. $10$ and $13$
• D. $12$ and $14$

Answer 1

Answer: (A)

$7$ and $10$

Let $x$ be the positive integer and $x+3$ be the largest integer
So, $x(x+3)=70$
$x^2+3x-70=0$
On factoring, we get,
$(x+10)(x-7)=0$
$x=-10$ or $x=7$
The largest integer $=x+3=7+3=10$
Therefore, the two numbers are $7$ and $10$.