Let three matrices A - - 2 1- 4 1 - B- 3 4- 2 3 - and C - - 3 -4- -2 3 - then trA-tr ABC-2 -tr ABC2-4 -tr ABC3-8 -

The correct option is C 6Let S=t_r(A)+t_r ( ABC/2 )+t_r ( A(BC)^2/4 )+t_r ( A(BC)^3/8 )+....+∞ BC=[ 3 amp; 4; 2 amp; 3 ][ 3 amp; 4; ...

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Determinant

Let three mat...

Question

Let three matrices A = $[\begin{matrix} 2 & 1 4 & 1 \end{matrix}]; B = [\begin{matrix} 3 & 4 2 & 3 \end{matrix}] a n d C = [\begin{matrix} 3 & - 4 - 2 & 3 \end{matrix}]$ then
$t_{r} (A) + t_{r} (\frac{A B C}{2}) + t_{r} (\frac{A (B C)^{2}}{4}) + t_{r} (\frac{A (B C)^{3}}{8}) + . . . . + \infty$

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A = [\begin{matrix} 2 & 1 4 & 1 \end{matrix}], B = [\begin{matrix} 3 & 4 2 & 3 \end{matrix}] and C = [\begin{matrix} 3 & - 4 - 2 & 3 \end{matrix}],

t r (A) + t r (\frac{A B C}{2}) + t r (\frac{A (B C)^{2}}{4}) + t r (\frac{A (B C)^{3}}{8}) + . . . \infty

A = [\begin{matrix} 2 & 1 4 & 1 \end{matrix}]

B = [\begin{matrix} 3 & 4 2 & 3 \end{matrix}]

C = [\begin{matrix} 3 & - 4 - 2 & 3 \end{matrix}]

t r (A) + t r (\frac{A B C}{2}) + t r (\frac{A {(B C)}^{2}}{4}) + t r (\frac{A {(B C)}^{3}}{8}) + . . . . . . . . + \infty =

A = [\begin{matrix} 2 & 1 4 & 1 \end{matrix}] B = [\begin{matrix} 3 & 4 2 & 3 \end{matrix}]

C = [\begin{matrix} 3 & - 4 - 2 & 3 \end{matrix}]

t r (A) + t r (\frac{A B C}{2}) + t r (\frac{A ({B C)}^{2}}{4}) + t r (\frac{A ({B C)}^{3}}{8}) + . . . . . . . . . . . . . + \infty

t r (A)

A

A = [\begin{matrix} 2 & 1 4 & 1 \end{matrix}]

B = [\begin{matrix} 3 & 4 2 & 3 \end{matrix}]

C = [\begin{matrix} 3 & - 4 - 2 & 3 \end{matrix}]

t r (A) + t r (\frac{A B C}{2}) t r (\frac{A {(B C)}^{2}}{4}) + t r (\frac{A {(B C)}^{3}}{8}) + . . . . + \infty

t r (A)

A

A B C = I

tr (A B C + B C A + C A B)

A, B, C

3

tr (A)

A

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