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Question

Let three vectors a, b and c be such that c is coplanar with a and b, a·c=7 and b is perpendicular to c where a=-i^+j^+k^ and b=2i^+k^ then the value of 2a+b+c2 is _______.


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Solution

Step 1: Finding c

Given the three vectors a, b and c.

Since c is coplane with a and b.

abc=0

Also, it is given that b is perpendicular to c.

b·c=0

Let c=λb×a×b

c=λb·ba-a·bb=λb2a-a·bb

Find the value of b using the given b.

b2=4+0+1=5

And the dot product of a and b.

a·b=-1

Now substituting all the obtained values in c=λb2a-a·bb.

c=λ5·-i^+j^+k^--12i^+k^=λ-5i^+5j^+5k+2i^+k^=λ-3i^+5j^+6k^

Step 2: Finding the value of λ

We have given that a·c=7 using the condition we find the value λ.

a·c=7-i^+j^+k^·λ-3i^+5j^+6k^=7λ3+5+6=714λ=7λ=12

Step 3: Finding the value of 2a+b+c2

Substitute the value of λ as 12 in c=λ-3i^+5j^+6k^.

c=12-3i^+5j^+6k^=-32i^+52j^+3k^

Now find the value of a+b+c

a+b+c=-i^+j^+k^+2i^+k^+-32i^+52j^+3k^=-i^+j^+k^+2i^+k^-32i^+52j^+3k^=-12i^+72j^+5k^

Using the above result find 2a+b+c2

2a+b+c2=2122+722+522=214+494+252=21+49+1004=21504=75

Therefore, the value of 2a+b+c2 is 75.


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