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Question

Let three vectors a,b and c be such that c is coplanar with a and b, a.c=7 and b is perpendicular to c, where a=^i+^j+^k and b=2^i+^k, then the value of 2|a+b+c|2 is

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Solution

Let c=λ(b×(a×b))
=λ((b.b)a(b.a)b)
=5λ((^i+^j+^k)+2^i+^k)
=λ(3^i+5^j+6^k)
c.a=73λ+5λ+6λ=7
λ=12
2(321+2)^i+(52+1)^j+(3+1+1)^k2
=2(14+494+25)=25+50=75

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