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Question

Let tr(X) and adj(X) denote the trace and adjoint of a square matrix X. If M is a non-singular square matrix of order 3 such that M1=345453534, then the value of |15tr(adj(M))| is

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Solution

M1=345453534
|M1|=3(209)4(1615)+5(1225)
|M1|=36
and tr(M1)=3+5+4=12

We know that M1=adj(M)|M|
adj(M)=|M|M1
tr(adj(M))=|M|tr(M1)
tr(adj(M))=136×12=13
|15tr(adj(M))|=15×(13)=5

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