Question

Let $△ABC\sim △DEF$ and there areas be, respectively $64c{m}^2$ and $121c{m}^2$ if $EF=15.4cm$ find $BC$ ?

Answer 1

$BC=1.07cm$

Given two similar triangles$\Delta ABC\Delta DEF$ and also their are as are respectively${64cm}^2$and${121cm}^2$Also if one of the sidei .e$EF=15.4cm$ then we have to find the side$BC.$

$\frac{area\left(ABC\right)}{area\left(DEF\right)}=\frac{{BC}^2}{{EF}^2}$

$\frac{64}{121}=\frac{{BC}^2}{{15.4}^2}$

$\frac{8}{11}=\frac{BC}{3.92}$

$BC=1.07cm$