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Question

Let PQR be a triangle. Let a=QR,b=RP and c=PQ. If |a|=12,|b|=43 and b.c=24, then which of the following is (are) true?

A
|c|22|a|=12
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B
|c|22+|a|=30
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C
|a×b+c×a|=483
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D
a.b=72
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Solution

The correct options are
A |c|22|a|=12
C |a×b+c×a|=483
D a.b=72
As PQR is a triangle,
So, a+b+c=0
|b+c|2=|a|2|b|2+|c|2+2bc=|a|2|c|2=48

Option (1):
|c|22|a|=2412=12
Option (1) is correct.

Option (2):
|c|22+|a|=24+12=36
Option (2) is not correct.

Now, a+b+c=0a.b+b.b+c.b=0a.b=4824=72
Option (4) is correct.

a.b=72
|a||b|cosθ=72
cosθ=32
θ=5π6

a+b+c=0
a×a+a×b+a×c=0a×b=(a×c)=c×a
|a×b+c×a|=2|a×b|=483
Option (3) is correct.

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