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Question

Let two circles with radii r1 and r2 have their centers at a distance of 2(r1r2).
If r1 and r2 are roots of the equation x22(α+β)x+α2+β2=0, then the relation between α and β for which the two circles are orthogonal is

A
α2+β2=4αβ
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B
(α+β)2=4αβ
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C
α2+β2=αβ
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D
α2β2=4αβ
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Solution

The correct option is B α2+β2=4αβ
For orthogonal of the two circles
c1c22=r12=r22
2(r1r2)2=r12+r22
r12+r22=4r1r2
2(α+β)2+4αβ=4[(α+β)22αβ]
(α+β)2=6αβ
a2+β2=4αβ

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