Let two circles with radii r1 and r2 have their centers at a distance of √2(r1−r2). If r1 and r2 are roots of the equation x2−2(α+β)x+α2+β2=0, then the relation between α and β for which the two circles are orthogonal is
A
α2+β2=4αβ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(α+β)2=4αβ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
α2+β2=αβ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
α2−β2=4αβ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Bα2+β2=4αβ For orthogonal of the two circles c1c22=r12=r22 2(r1−r2)2=r12+r22 r12+r22=4r1r2 2(α+β)2+4αβ=4[(α+β)2−2αβ] (α+β)2=6αβ a2+β2=4αβ