Question

Let two equal chords of a circle are $AX$ and $BY.$ If chord $AX$ substends ${50}^{\circ }$ at centre, then angle substends by chord $BY$ is

• A. ${40}^{\circ }$
• B. ${50}^{\circ }$
• C. ${100}^{\circ }$
• D. ${25}^{\circ }$

Answer 1

The correct option is B ${50}^{\circ }$

Equal chords subtend equal angles at the center of a circle

Here $AX=BY$
$\therefore \angle BOY=\angle AOX={50}^{\circ }$