Let two like parallel forces are acting, at points A and B such that the force at A is double than the force at B. If C is the point of action of the resultant, then AC/BC is
A
2
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B
1/2
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C
1/3
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D
1/4
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Solution
The correct option is B1/2 Since, AC=(AB)P2P+P ⇒3AC=(AC+BC) ⇒ACBC=12