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Question

Let two like parallel forces are acting, at points $$A$$ and $$B$$ such that the force at $$A$$ is double than the force at $$B$$. If $$C$$ is the point of action of the resultant, then $$AC/BC$$ is


A
2
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B
1/2
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C
1/3
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D
1/4
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Solution

The correct option is B $$1/2$$
Since, $$AC=\cfrac { (AB)P }{ 2P+P } $$
$$\Rightarrow 3AC=(AC+BC)$$
$$\Rightarrow \cfrac { AC }{ BC } =\cfrac { 1 }{ 2 } $$
730716_661167_ans_84ed8081ed4143cab95f5e09da7b44df.png

Physics

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