Question

# Let two like parallel forces are acting, at points $$A$$ and $$B$$ such that the force at $$A$$ is double than the force at $$B$$. If $$C$$ is the point of action of the resultant, then $$AC/BC$$ is

A
2
B
1/2
C
1/3
D
1/4

Solution

## The correct option is B $$1/2$$Since, $$AC=\cfrac { (AB)P }{ 2P+P }$$$$\Rightarrow 3AC=(AC+BC)$$$$\Rightarrow \cfrac { AC }{ BC } =\cfrac { 1 }{ 2 }$$Physics

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