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Question

Let two planes p1:2xy+z=2, and p2:x+2yz=3 are given. The equation of the bisector of angle of the planes P1 and P2 which does not contains origin, is

A
x3y+2z+1=0
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B
x+3y=5
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C
x+3y+2z+2=0
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D
3x+y=5
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Solution

The correct option is A 3x+y=5
Given planes are p1:2xy+z=2 and p2:x+2yz=3

Normals to the planes
N1:16(2,1,1)
N2:16(1,2,1)
Let N be the normal vector of angle bisector
N=N1+N2 or N1N2
N=(3,1,0) or (1,3,2)
The equation of plane is
P=P1+λP2
P=2xy+z2+λ(x+2yz3)
If N=(3,1,0), then λ=1,
Equation of Plane =P=3x+y5
It does not pass through origin.

Hence, option D is correct.

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