Let two planes p1:2x−y+z=2, and p2:x+2y−z=3 are given. The equation of the bisector of angle of the planes P1 and P2 which does not contains origin, is
A
x−3y+2z+1=0
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B
x+3y=5
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C
x+3y+2z+2=0
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D
3x+y=5
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Solution
The correct option is A3x+y=5
Given planes are p1:2x−y+z=2and p2:x+2y−z=3
Normals to the planes
N1:1√6(2,−1,1) N2:1√6(1,2,−1)
Let N be the normal vector of angle bisector N=N1+N2 or N1−N2 N=(3,1,0) or (1,−3,2) The equation of plane is P=P1+λP2 P=2x−y+z−2+λ(x+2y−z−3)
If N=(3,1,0), then λ=1, Equation of Plane =P=3x+y−5 It does not pass through origin.