Question

Let $u$ and $v$ be two odd functions, then the function uov is

• A. An even function
• B. An odd function
• C. Neither even nor odd
• D. A periodic function

Answer 1

Answer: (B)

An odd function

We have, $uov(-x)$
$=u\left[v\right(-x\left)\right]$
$=u[-v(x\left)\right]$ [ $\because$ v is odd]
$=-u\left[v\right(x\left)\right]$ [ $\because$ u is odd]
$=-uov\left(x\right)$
Thus, $uov$ is an odd function.