Let U be the set of all triangles in a plane. If A is the set of all triangles with at least one angle different from 60°, what is ?
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Solution
U=set of all triangles
Thus,
U={x:x is a triangle}
A=set of all triangles with atleast one angle different from 60°.
Therefore,
, A ′=U−A={x:x is a triangle}−{x:x is a triangle with atleast one angle different from 60°}={x:x is a triangle and no angles different from 60°}={x:x is a triangle with all anglesas 60°}
Thus, A ′ is a set of all theequilateral triangles.