Let U be the universal set for sets A and B such that nA-200 - nB-300 and nA- B-100- then nA- B- is equal to 300 provided that nU is equal to

Let U be the universal set containing 700 elements. If A, B are sub-sets of U such that n (A) = 200, n(B) =300 and $n (A \cap B)$ = 100. Then , $n (A^{'} \cap B^{'}) =$

Q. Let

n (U) = 700, n (A) = 200, n (B) = 300

and

n (A \cap B) = 100

, then

n (A^{c} \cap B^{c})

equals to

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Let U be the universal set for sets A and B such that n(A)=200,n(B)=300 and n(A∩B)=100, then n(A′∩B′) is equal to 300 provided that n(U) is equal to

The correct option is A 700n(A∪B)=n(A)+n(B)−n(A∩B)=200+300−100=400n(A′∩B′)=n(A∪B)′ =n(U)−n(A∪B)300=n(U)−400n(U)=700

Let $U$ be the universal set for sets $A$ and $B$ such that $n (A) = 200, n (B) = 300$ and $n (A \cap B) = 100$ , then $n (A^{'} \cap B^{'})$ is equal to $300$ provided that $n (U)$ is equal to

The correct option is A $700$
$n (A \cup B) = n (A) + n (B) - n (A \cap B)$
$= 200 + 300 - 100$
$= 400$
$n (A^{'} \cap B^{'}) = n (A \cup B)^{'}$
$= n (U) - n (A \cup B)$
$300 = n (U) - 400$
$n (U) = 700$