Question

Let us consider the ionization of $HCl$ in the aqueous solution of ${CH}_{3}COOH$.
${CH}_{3}COOH+HCl\rightleftharpoons {CH}_{3}COO{H}_2^{+}+{Cl}^{-}$
Select the correct statement(s) among the following:

• A. ${Cl}^{-}$ is the conjugate base of $HCl$
• B. ${CH}_{3}COOH$ is the conjugate base of ${CH}_{3}COO{H}_2^{+}$
• C. ${CH}_{3}COO{H}_2^{+}$ is the conjugate base of ${CH}_{3}COOH$
• D. ${Cl}^{-}$ is the conjugate base of ${CH}_{3}COOH$

Answer 1

Answer: (A), (B)

${Cl}^{-}$ is the conjugate base of $HCl$
${CH}_{3}COOH$ is the conjugate base of ${CH}_{3}COO{H}_2^{+}$

In the given reaction,

${CH}_{3}COOH+HCl\rightleftharpoons {CH}_{3}COO{H}_2^{+}+{Cl}^{-}$

A acid will donate its proton or $H^{+}$ ions and the base will accept the $H^{+}$ ion.

In this case, $C{H}_{3}COOH$ accepts $H^{+}$ ion from $HCl$.So $C{H}_{3}COOH$ is base and $HCl$ is acid.

Now Conjugate base of an acid, $HCl$ is $C{l}^{-}$ and conjugate acid of base, $C{H}_{3}COOH$ is $C{H}_{3}COO{H}_2^{+}$ .

Options A,B are correct.