Let us suppose that earth (radius 6400 km) had a net charge equivalent to one electron per m $^{2}$ of its surface area. Its potential in volts will be:

- 1.2

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- 0.12

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0.12

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1.2

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Solution

The correct option is A $- 0.12$
Consider earth as a big conducting sphere with $σ = - 1.6 \times 10^{- 19}$ $C m^{- 2}$
potential of a conducting sphere $= k σ 4 π R$
$= 9 \cdot 10^{9} \times - 1.6 \cdot 10^{- 19} \times 4 π \times 6400 \cdot 10^{3}$
$\approx - 0.12 V$

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Let us suppose that earth (radius 6400 km) had a net charge equivalent to one electron per m2 of its surface area. Its potential in volts will be:

The correct option is A −0.12Consider earth as a big conducting sphere with σ=−1.6×10−19 Cm−2potential of a conducting sphere=kσ4πR=9⋅109×−1.6⋅10−19×4π×6400⋅103≈−0.12V

Let us suppose that earth (radius 6400 km) had a net charge equivalent to one electron per m $^{2}$ of its surface area. Its potential in volts will be:

The correct option is A $- 0.12$
Consider earth as a big conducting sphere with $σ = - 1.6 \times 10^{- 19}$ $C m^{- 2}$
potential of a conducting sphere $= k σ 4 π R$
$= 9 \cdot 10^{9} \times - 1.6 \cdot 10^{- 19} \times 4 π \times 6400 \cdot 10^{3}$
$\approx - 0.12 V$