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Question

Let a=2i3j+4k and b=i2k, then find an unit vector in the direction of 2ab.

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Solution

Given,
a=2i3j+4k and b=i2k.
Now,
2ab
=2(2i3j+4k)(i2k)
=3i6j+10k.
Now, |2ab|=32+62+102=145.
So an unit vector in the direction of 2ab is 2ab|2ab|=3i6j+10k145


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