→a=4i+5j−k
→b=i−4j+5k
→c=3i+j−k
Let →d=xi+yj+zk
Therefore according to question:-
→d.→c=21
(xi+yj+zk).(3i+j−k)=21(becausei.i=j.j=k.k=1)
On solving the above equation we get 3x+y−z=21 ................(let equation 1)
We know that when two vectors are perpendicular then dot product of two vectors is equal to zero
Therefore →d.→a=0
(xi+yj+zk).(4i+5j−k)=0
i.e. 4x+5y−z=0...................(let equation 2)
Therefore →d.→b=0
(xi+yj+zk).(i−4j+5k)=0
i.e. x−4y+5z=0 ..................(let equation 3)
Now on adding equation1 and equation 3 and subtract it sum from equation 2
We get 8y−5z=−21.................(let equation 4)
On multiplying equation 3 by 3 and subtract it from equation 1
We get 13y−16z=21................(let equation 5)
On solving equation 4 and equation 5
We get y=z=−7
Now on putting value of y and z in equation equation 3
We get x=7
Therefore →d=7i−7j−7k