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Question

Let a=6i3j6k and d=i+j+k.Suppose that a=b+c where b is parallel to d and c is perpendicular to d. Then c is

A
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C
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D
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Solution

The correct option is B
a=6i3j6kd=i+j+ka=b+c...............(1)b=λd & c.d=0b=λ^i+λ^j+λ^kFrom(1)6^i3^j6^k=λ^i+λ^j+λ^k+cc=(6λ)^i(3+λ)^j(6+λ)^kc.d=0λ=1c=7^i2^j5^k

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