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Question

Let a=a1^i+α2^j+a3^k, b=b1^i+b2^j+b3^k and c=c1 ^i+c2 ^j+c3 ^k be three non-zero vectors such that c is a unit vector perpendicular to both the vectors a and b. If the angle between a and b is π6,
then ∣ ∣a1a2a3b1b2b3c1c2c3∣ ∣2 is equal to


A

0

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B

1

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C

14(a21+a22+a23)(b21+b22+b23)

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D

34(a21+a22+a23)(b21+b22+b23)(c21+c22+c23)

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Solution

The correct option is C

14(a21+a22+a23)(b21+b22+b23)


Since, (a×b)=|a||b| sinπ6.^n(a×b).c=12|a||b|.^n.c[a b c]=12|a||b|.cos 0
^n is perpendicular to both a,b and c is also a unit vector perpendicular to both a and b.
∣ ∣a1a2a3b1b2b3c1c2c3∣ ∣2=[a b c]2=14.|a|2|b|2=14(a21+a22+a23)(b21+b22+b23)


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