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Question

Let A=a^i+b^j+c^k be a unit vector and B is another vector in R3 such that |A×B|=1,C=13(2^i+2^j^k) and (A×B).C= 1, then which of the following statement(s) is/are correct?


A

If A lies in plane x + y + z = 0, then there are exactly two choices for A

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B

If A lies in plane x + y + z = 0, then there are exactly 4 choices for A

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C

If a, b, c ϵ I, then there is no such vector A

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D

If a, b, c ϵ I, then there infinitely many choices for A

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Solution

The correct options are
A

If A lies in plane x + y + z = 0, then there are exactly two choices for A


C

If a, b, c ϵ I, then there is no such vector A


C=A×BA.C=0
2a+2bc=0
For (A) and (B) a+b+c=0c=0;a+b=0
As a2+b2+c2=1(12,12,0)(12,12,0)
For (C) and (D)
a2+b2+c2=12a+2b=c} are not satisfied for any triplet of integers


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