Let →A=a^i+b^j+c^k be a unit vector and →B is another vector in R3 such that |→A×→B|=1,→C=13(2^i+2^j−^k) and (→A×→B).→C= 1, then which of the following statement(s) is/are correct?
If →A lies in plane x + y + z = 0, then there are exactly two choices for →A
If a, b, c ϵ I, then there is no such vector →A
→C=→A×→B⇒→A.→C=0
⇒2a+2b−c=0
For (A) and (B) a+b+c=0⇒c=0;a+b=0
As a2+b2+c2=1⇒⎧⎪⎨⎪⎩(−1√2,1√2,0)(1√2,−1√2,0)
For (C) and (D)
a2+b2+c2=12a+2b=c} are not satisfied for any triplet of integers