Let a- and b- are two vectors in space such that a-3-5-k-35- b-5i-j-10k-126- then the value of -a-b-a-2b-a-b- is equal to-

a⃗ = 3î +5ĵ k̂ #160; /√( 35 ) #160; ,b⃗ = 5î ĵ +10k̂ #160; /√( 126 ) #160; #160; Then, [ a⃗ +b⃗·a⃗ +2b⃗a⃗×b⃗ #160; ] #160; ⇒ ...

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Right Hand Limit

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Question

Let $\to a$ and $\to b$ are two vectors in space such that $\to a = \frac{3^i + 5^j -^k}{\sqrt{35}}, \to b = \frac{5 i - j + 10^k}{\sqrt{126}}$ , then the value of $[\to a + \to b \to a + 2 \to b \to a \times \to b]$ is equal to?

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\to a

\to b

| \to a + \to b | = \sqrt{3}

(2 \to a + 5 \to b) \cdot (3 \to a + \to b + \to a \times \to b)

\to a

\to b

| \to a + \to b | = \sqrt{3} .

\to c = \to a + 2 \to b + 3 (\to a \times \to b),

2 | \to c |

\to a

\to b

| \to a | = 3

| \to b | = 6

| \to a + \to b | = 7

(3 \to a - 2 \to b) . (2 \to a + 5 \to b - 4 \to a \times \to b)

\to a

\to b

| \to a + \to b | = \sqrt{29}

\to a \times (2^i + 3^j + 4^k) = (2^i + 3^j + 4^k) \times \to b

(\to a + \to b) \cdot (- 7^i + 2^j + 3^k)

\to a

\to b

| \to a | = 3

| \to b | = \frac{\sqrt{2}}{3}

\to a \times \to b

\to a

\to b

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