Let a- and b- be two unit vectors then a-b- will also be a unit vector if

The correct option is B a⃗⊥b⃗ If a⃗×b⃗ is unit #160;vector than #160; | a⃗×b⃗ |=1 | a⃗×b⃗ |= | a⃗ | | b⃗ |sinθ 1=sinθ θ =90^0 ...

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Applications of Cross Product

Let a⃗ and ...

Question

Let $\to a$ and $\to b$ be two unit vectors then $\to a \times \to b$ will also be a unit vector if

\to a = \to b

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\to a ⊥ \to b

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\to a | | \to b

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\to a = m \to b

m > 1

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Solution

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\to a

\to b

\to a + \to b

\to a

\to b

\to a

\to b

\frac{{∣ ∣ \to a + \to b ∣ ∣}^{2} - {∣ ∣ \to a - \to b ∣ ∣}^{2}}{{∣ ∣ \to a + \to b ∣ ∣}^{2} + {∣ ∣ \to a - \to b ∣ ∣}^{2}}

\to a, \to b

\to α = \to a - (\to a . \to b) \to b, \to β = \to a \times \to b

| \to a + \to b | = | \to a - \to b |

(\to a, \to b) = \frac{π}{2}

\to a, \to b, \to a + \to b

(\to a, \to b) = \frac{2 π}{3}

\to a

\to b

\to a + \to b

\to a

\to b .

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