Let, →a=^i+2^j+^k,→b=^i−^j+^k,→c=^i+^j−^k. A vector coplanar to →a and →b has a projection along →c of magnitude 1√3, then the vector is
A
4^i−^j+4^k
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B
4^i+^j−4k
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C
2^i+^j+^k
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D
None of these
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Solution
The correct option is A4^i−^j+4^k Let vector →r be coplanar to →a and →b.∴→r=→a+t→b⇒→r=(^i+2^j+^k)+t(^i−^j+^k)=^i(1+t)+^j(2−t)+^k(1+t) The projection of →r on →c=1√3. [given] ⇒→r.→c|→c|=1√3⇒|1.(1+t)+1.(2−t)−1.(1+t)|√3=1√3 ⇒(2−t)=±1⇒t=1or3 When, t = 1, we have →r=2^i+^j+2^k When, t = 3, we have →r=4^i−^j+4^k