Let a-k- b-3-k- and c-2-3k- then the ascending order of magnitudes of A -a-b- b-c- c-a- B -a-b- b-c- c-a- C -a- b- c- -a- b- c-1 D -a-b- b-c- c-a-

The correct option is B BCDA A) We have =((b̅×c̅)× (c̅×a̅))(a⃗×b⃗) =((b⃗×c⃗.a⃗)c⃗ (b⃗×c⃗.c⃗)a⃗)(a⃗×b⃗) =[a b⃗ c⃗]^2=9 [a⃗b⃗c⃗]=1 ...

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Formation of a Differential Equation from a General Solution

Let a⃗=î+ĵ+...

Question

Let $\to a =^i +^j +^k$ , $\to b = - 3^i +^k$ and $\to c =^i + 2^j + 3^k$ , then the ascending order of magnitudes of

$A)$ $[\to a \times \to b$ $\to b \times \to c$ $\to c \times \to a]$
$B)$ $[\to a + \to b$ $\to b + \to c$ $\to c + \to a]$
$C)$ $[\to a$ $\to b$ $\to c]$ $[\to a$ $\to b$ $\to c]^{- 1}$
$D)$ $[\to a - \to b$ $\to b - \to c$ $\to c - \to a]$

A B C D

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B C D A

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C B A D

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D B C A

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Solution

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Similar questions

\to A = \to b \times \to c, \to B = \to c \times \to a, \to C = \to a \times \to b

\to A \times (\to B \times \to C)

\to B \times (\to C \times \to A)

\to C \times (\to A \times \to B)

| \to a | = 1, ∣ ∣ \to b ∣ ∣ = \sqrt{2}

| \to c | = \sqrt{3}

\to a ⊥ (\to b + \to c)

\to b ⊥ (\to c + \to a)

\to c ⊥ (\to a + \to b)

∣ ∣ \to a + \to b + \to c ∣ ∣

[\to a + 2 \to b - \to c, \to a - \to b, \to a - \to b - \to c] =

(\to a + \to b) \times (\to a - \to b) + (\to b + \to c) \times (\to b - \to c) + (\to c + \to a) \times (\to c - \to a) =

\to a = 3^i + 2^j + 2^k, \to b = -^i + 3^j -^k, \to c =^i +^j +^k

\to a \times (\to b \times \to c)

(\to a \times \to b) \times \to c

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