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Question

Let a=^i+^j+^k,b=^i+3^j+5^k and c=7^i+9^j+11^k. Then the area of the parallelogram with diagonals a+b and b+c is

A
46
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B
1221
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C
62
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D
6
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E
16
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Solution

The correct option is A 46
a=^i+^j+^k
b=^i+3^j+5^k
c=7^i+9^j+11^k
Diagonals: D1=a+b D2=b+c
Area of parallelogram =12[D1×D2].......(i)
D1=a+b=2^i+4^j+6^k
D2=b+c=8^i+12^j+16^k
From Equation (i),
|Area|=12∣ ∣ ∣^i^j^k24681216∣ ∣ ∣

=12[^i(6472)+^j(4832)+^k(2432)]
=12|8^i+16^j8^k|

=1264+256+64=12.86=46

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