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Question

Let a=^i^j,b=^i+^j+^k and c be a vector such that a×c+b=0 and a.c=4, then |c|2 is equal to

A
192
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B
8
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C
172
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D
9
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Solution

The correct option is A 192
a×c=b
(a×c)×a=b×a
(a×c)×a=a×b
(a.a)c(c.a)a=a×b
2c4a=a×b
Now a×b=∣ ∣ ∣^i^j^k110111∣ ∣ ∣=^i^j+2^k
So, 2c=4^i4^j^i^j+2^k
=3^i5^j+2^k
c=32^i52^j+^k
|c|=94+254+1=384=192
|c|2=192.

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