Let a- - -k- b- - x - - -1- x k- and c- - y - - x - -1- x - y k- then -a- -b- -c- - depends on

The correct option is C Neither x nor y Given #160; a =î k̂ b =xî +ĵ +( 1 x ) k̂ c =yî +xĵ +( 1+x y ) k̂ We have #160; [ ...

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Cross Product of Two Vectors

Let a⃗ =î -...

Question

Let $\to a =^i -^k$ , $\to b = x^i +^j + (1 - x)^k$ and $\to c = y^i + x^j + (1 + x - y)^k$ , then $[\to a, \to b, \to c]$ depends on

Only

4 y

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Only

x

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Both

x

and

y

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Neither

x

nor

y

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Similar questions

\to a =^i -^k, \to b = x^i +^j + (1 - x)^k

\to c = y^i + x^j + (1 + x - y)^k,

[\to a \to b \to c]

¯ a =^i -^k, ¯ b = x^i +^j + (1 - x)^k

¯ c = y^i + x^j + (1 + x - y)^k

[¯ a ¯ b ¯ c]

\to a =^i +^j +^k

\to b = - 3^i +^k

\to c =^i + 2^j + 3^k

A)

[\to a \times \to b

\to b \times \to c

\to c \times \to a]

B)

[\to a + \to b

\to b + \to c

\to c + \to a]

C)

[\to a

\to b

\to c]

[\to a

\to b

\to c]^{- 1}

D)

[\to a - \to b

\to b - \to c

\to c - \to a]

\to a =^i +^j +^k, \to b =^i -^j + 2^k, \to c = x^i + (x - 2)^j -^k

x =

\to a =^i +^j +^k

\to b =^i -^j +^k

\to c =^i +^j -^k

\to a =^i -^j -^k

(\to a \times \to b) \times (\to c \times \to d)

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