Let a- - - - k- and c- - - - - - k- Then the vector b- satisfying a-b- - c- - 0- and a-b- - 3 is-

The correct option is A î + ĵ 2k̂ We have a⃗×b⃗+c⃗=0 ⇒ a⃗×(a⃗×b⃗)+a⃗×c⃗=0 ⇒ (a⃗.b⃗)a⃗ (a⃗.a⃗)b⃗+a⃗×c⃗=0 ⇒ 3a 2b+a⃗×c⃗=0 ⇒ 2b=3 ...

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Multiplication of a Vector by a Scalar

Let a⃗ = ĵ ...

Question

Let $\to a =^j -^k$ and $\to c =^i -^j -^k$ . Then the vector $\to b$ satisfying $\to a \times \to b + \to c = \to 0$ and $\to a . \to b = 3$ is:

-^i +^j - 2^k

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2^i -^j + 2^k

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^i -^j - 2^k

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^i +^j - 2^k

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Solution

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Similar questions

\to a =^i +^j +^k, \to c =^j -^k

\to b

\to a \times \to b = \to c

\to a . \to b = 3

| \to b |

\to a = 2^i +^j +^k

\to b =^i + 2^j + 2^k

\to c =^i +^j + 2^k

\to a \times (\to b \times \to c) = (1 + α)^i + β (1 + α)^j + r (1 + α) (1 + β)^k

\to A =^i - 2^j + 2^k, \to B = 2^i +^j -^k

\to C = 3^i -^j + 2^k

\to a =^i +^j +^k, \to b =^i -^j + 2^k, \to c = x^i + (x - 2)^j -^k

x =

\to a = 2^i + 4^j - 5^k, \to b =^i +^j +^k, \to c =^j + 2^k

\to a + \to b + \to c

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